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Posted

Does this help: https://en.wikipedia.org/wiki/Priority_encoder

Actually, it might not because the first paragraph is incomprehensible. But the second paragraph is clearer. Basically, it has a number of input bits which are in priority order, and it tells you the highest priority bit that is set.

I'm afraid I am not going to try and work out what it does in that system. Presumably it chooses the next person to be processed.

Posted

Hi,

Thanks for your reply and link. If there is no encryption, how are we having security in the above circuitry?

 

Somebody please guide me.

 

Zulfi.

Posted

Hi,

I got following text from the paper:

Quote

In secure stable matching, the match list is computed while
keeping the preference lists private to their respective owners.
This problem has been studied in the recent literature [21],
[22] where the secure stable matching problem is reduced to a
two-party secure computation scenario. Each individual XORshares
her preference list and sends it to two non-colluding
servers who perform the secure computation. However, stable
matching is inherently a multi-party problem and the assumption
of two non-colluding servers may not be feasible in
practice. To the best of our knowledge, we provide the first
solution for multi-party secure stable matching.

I can't understand why its multi-party circuit? Its inputting two groups. But how its performing n * n  computation instead of 2 * 2 computation.

 

Somebody please guide me.

Zulfi

Posted
Just now, zak100 said:

I can't understand why its multi-party circuit? Its inputting two groups. But how its performing n * n  computation instead of 2 * 2 computation.

 

n = 2

Posted

Hi,

Thanks for your response.

Don't we have two groups in multi-party computation? Figure shows that the circuit can only input two groups. How in case of multi-party computation, the circuit uses the two groups to do n * n computation?

 

Zulfi.

Posted

Hi,

Sorry correcting above:

 

Can't we input only two groups in the above figure? Figure shows that the circuit can only input two groups. How in case of multi-party computation, the circuit uses the two groups to do n * n computation?

Zulfi.

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