NineTwentyEight Posted May 13, 2020 Posted May 13, 2020 (edited) The deviation should not be as perfectly symmetrical as your charts indicate. First of all what is particle duality, there must be a hidden world of variables, like dark matter - causing two specific effects as well as a particle being in two places at once: Double slit, if it's dark matter take the elementary particle and reverse it's charge to get your hidden variable. Particle asymmetry is broken after a duration passes, reverse that asymmetry and you get your pair which is tangible. So for the double slit, the photons used to see into the beam adds thermal energy to the system, this heat is like glue. But if you have a hidden world of asymmetric particles at that location it will not experience changes in temperature from the light being reflected, so you see it in lower numbers when it hits the target, however the asymmetric intangible particles have asymmetric baryonic counterparts during a planck scale evolution this is what we observe. Quantum Venn diagram paradox, same principle the asymmetric world adopts slightly deviated polarities which can pass through the filters created from the baryonic asymmetry of the intangible asymmetric counterparts of said particles. One might ask about the dark matter/elementary particles, their nature, and their origin. I'd simply explain that if the universe ends, looking at events in reverse will create a slightly different universe shadowed by our own, and vice versa The real planck density is 9 orders of magnitude smaller, but those pairs kick in to compensate which is why the density is lower than we've predicted. Also you will notice that the planck mass is the energy of a photon focused within the volume existing between all the gravitons that compose that photon. Secondly, you're using two dimension. Remember you can get any of a dozen conic sections and their opposite using a^2 + b^2 = C^2 This is the proper technique for building sphere out of symmetric conic section, made from the triangle: Quadrant 1 f(C(x1)) = C/2pi f(C(y1) = C/pi f(C(x2)) = ((f(C(x1))) + (f(C(y1)))) / 2 = f(C(y2)) f(C(x3)) = f(C(y1)) f(C(y3)) = f(C(x1)) etc Edited May 13, 2020 by NineTwentyEight
Strange Posted May 13, 2020 Posted May 13, 2020 ! Moderator Note Please do not hijack other people's threads with your own speculation
NineTwentyEight Posted May 13, 2020 Author Posted May 13, 2020 (edited) a1/b1 for the triangle represents one quadrant of the square you'r turning into a circle, you double it to get a2/b2 and that's one of two sides. x or y +/- ((n[x or y] - (n - n(1/2r))) to show the depth increase or loss in the 3rd dimension even on 2D graphing paper. That's how Apple GPS is better than just unfolding an oval planetary surface. Edited May 13, 2020 by NineTwentyEight
Strange Posted May 13, 2020 Posted May 13, 2020 ! Moderator Note You are not making much sense. If you cannot make a clear statement of what you want to discuss, this thread will be closed.
NineTwentyEight Posted May 13, 2020 Author Posted May 13, 2020 (edited) 20 minutes ago, Strange said: ! Moderator Note You are not making much sense. If you cannot make a clear statement of what you want to discuss, this thread will be closed. Well I wasn't making a topic, I was discussing a theoretical way to explain the wave function. This is why we only use a fraction of our mind's computing power, or have been unsuccessful in acquiring energy from the vacuum. But it needed a basis in calculus regarding 3D topology which is why I added those Newtonian functions. Edited May 13, 2020 by NineTwentyEight
NineTwentyEight Posted May 15, 2020 Author Posted May 15, 2020 (edited) Wrong thread Edited May 15, 2020 by NineTwentyEight
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now