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ok here is question and my answers...:

 

[math]

\lambda=2L=2\times0.580m=1.16m

[/math]

 

[math]

\mu=\frac{M}{L_(wire)}=\frac{0.00225kg}{1.00m}=0.00225(kg/m)

[/math]

 

[math]

v=\sqrt{\frac{F}{\mu}}=\sqrt{\frac{29.4N}{0.00225}}=114.3(m/s)

[/math]

 

[math]

f=\frac{v}{\lambda}=\frac{114.3(m/s)}{1.16m}=98.54 \ Hz=98.5 \ Hz

[/math]

 

how'd i do?

 

-Sarah :)

Picture 5.png

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