Sarahisme Posted August 14, 2005 Posted August 14, 2005 ok here is question and my answers...: [math] \lambda=2L=2\times0.580m=1.16m [/math] [math] \mu=\frac{M}{L_(wire)}=\frac{0.00225kg}{1.00m}=0.00225(kg/m) [/math] [math] v=\sqrt{\frac{F}{\mu}}=\sqrt{\frac{29.4N}{0.00225}}=114.3(m/s) [/math] [math] f=\frac{v}{\lambda}=\frac{114.3(m/s)}{1.16m}=98.54 \ Hz=98.5 \ Hz [/math] how'd i do? -Sarah
Sarahisme Posted August 15, 2005 Author Posted August 15, 2005 i take that as an, everything is perfectly correct??
DQW Posted August 16, 2005 Posted August 16, 2005 i take that as an, everything is perfectly correct??
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