Frogger Posted August 5, 2020 Share Posted August 5, 2020 Dim I(1 to 24) For n=1 to 10 I(1)=((2n)-1) I(2)=n I(3)=n I(4)=n I(5)=n I(6)=(n-(n×(n-1))) I(7)=n I(8)=1 I(9)=n I(10)=((2n)-1) I(11)=n I(12)=n I(13)=n I(14)=n I(15)=1 I(16)=n I(17)=(n×n) I(18)=n I(19)=(n×n) I(20)=n I(21)=n I(22)=n I(23)=n I(24)=(n-(n×(n-1))) Next n -1 Link to comment Share on other sites More sharing options...
Strange Posted August 5, 2020 Share Posted August 5, 2020 ! Moderator Note If you want to discuss something, you need to explain what it is that you want to discuss. And try to post in the right section of the forum: this appears to have nothing to do with Science Education. Link to comment Share on other sites More sharing options...
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