Frogger Posted August 5, 2020 Posted August 5, 2020 Dim I(1 to 24) For n=1 to 10 I(1)=((2n)-1) I(2)=n I(3)=n I(4)=n I(5)=n I(6)=(n-(n×(n-1))) I(7)=n I(8)=1 I(9)=n I(10)=((2n)-1) I(11)=n I(12)=n I(13)=n I(14)=n I(15)=1 I(16)=n I(17)=(n×n) I(18)=n I(19)=(n×n) I(20)=n I(21)=n I(22)=n I(23)=n I(24)=(n-(n×(n-1))) Next n -1
Strange Posted August 5, 2020 Posted August 5, 2020 ! Moderator Note If you want to discuss something, you need to explain what it is that you want to discuss. And try to post in the right section of the forum: this appears to have nothing to do with Science Education.
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