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Posted (edited)

the mole ratio of acid: salt in production of an acidic buffer solution is between 1/10 to 10/1. 

5mol HCOOH + 5mol KOH isn't a buffer solution, why? 

1mol HCOOH + 1mol HCOOK is a buffer solution, why?

 

Edited by mundane
Posted (edited)

A buffer solution is an equilibrium mixture of either a (weak) acid and its conjugate base or a (weak) base and its conjugate acid.

So firstly you need to identify the acids, bases and conjugates in the two situations and whether they are strong or weak ?

Have you done this ?

Pudue University migh help you here

https://chemed.chem.purdue.edu/genchem/topicreview/bp/ch17/mixtures.php

Edited by studiot
Posted
On 10/17/2020 at 8:52 PM, mundane said:

the mole ratio of acid: salt in production of an acidic buffer solution is between 1/10 to 10/1. 

5mol HCOOH +Tell us more about what your goals are regarding buffers, then we can maybe get to some conclusion.  5mol KOH isn't a buffer solution, why? 

1mol HCOOH + 1mol HCOOK is a buffer solution, why?

 

Who said that the above is true?? I make buffers every day. Tell us what your goals are regarding buffers then we can get somewhere.  

 

  • 3 weeks later...
Posted
Quote

A buffer solution (more precisely, pH buffer or hydrogen ion buffer) is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa

 

On 10/18/2020 at 3:52 AM, mundane said:

the mole ratio of acid: salt in production of an acidic buffer solution is between 1/10 to 10/1. 

5mol HCOOH + 5mol KOH isn't a buffer solution, why? 

1mol HCOOH + 1mol HCOOK is a buffer solution, why?

 

In first case will be a neutralization reaction between a weak acid and a strong base

5 mol HCOOH+5mol KOH=5 mol HCOOK+5 mol HOH    

Products are a salt (a conjugate  base  of a weack acid )and water

6 mol HCOOH+5 mol KOH=1 mol HCOOH+5 mol HCOOK+5 mol HOH  is a buffer solution

 

 

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