applede Posted November 24, 2020 Posted November 24, 2020 Can anyone solve this problem? the unlabeled reagent bottles contain sodium carbonate, calcium carbonate, barium sulphate, sodium chloride and sodium sulphate, how with distilled water, dilute HCl and barium chloride solution can determine what is in which reagent bottle.Show with reactions with aggregate states. Thank you so much for reponse, if it possible can someone solve this problem completly i now that elements of first group are soluable in water and barium sulphate and calcium carbonate are not but can you slove please, thanks
joigus Posted November 24, 2020 Posted November 24, 2020 People will give you hints, not solve the problem for you. That's against the rules.
studiot Posted November 24, 2020 Posted November 24, 2020 What have you done so far ? I would start by numbering the bottles A, B ,C, D and E. Then perhaps prepare a reaction table of combining small samples from all pairs of bottles. 1
Sensei Posted November 24, 2020 Posted November 24, 2020 14 minutes ago, applede said: the unlabeled reagent bottles contain sodium carbonate, calcium carbonate, barium sulphate, sodium chloride and sodium sulphate, how with distilled water, dilute HCl and barium chloride solution can determine what is in which reagent bottle.Show with reactions with aggregate states. How carbonates and bicarbonates react with strong acid? What happens with them?
applede Posted November 24, 2020 Author Posted November 24, 2020 i know there is co2 and bubbles but how i can know where is Na and where is Ca
studiot Posted November 24, 2020 Posted November 24, 2020 Reading this more thoroughly I think the bottles must all contain white powders, not solutions as I originally thought. So you will have to make you own solutions. So you should add two further actions to your table: Solubility in water and solubility in dilute HCl. Are all the reagents listed going to be soluble in both ?
hypervalent_iodine Posted November 25, 2020 Posted November 25, 2020 1 hour ago, studiot said: Reading this more thoroughly I think the bottles must all contain white powders, not solutions as I originally thought. So you will have to make you own solutions. So you should add two further actions to your table: Solubility in water and solubility in dilute HCl. Are all the reagents listed going to be soluble in both ? Solubility in barium chloride as well.
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