Neptune Posted December 21, 2020 Share Posted December 21, 2020 I wanted to share a few Algebraic physics formulas, a couple I created and other established ones, and wanted to get the community's reaction and input. Also if the my ideas get big, I want to call them Neo-Classical Physics. Incase it isn't obvious the ones I created are the rPhoton and gPhoton formulas. I'd like to ask you to review them with your own inputs of different photon frequencies or wavelengths to find errors of them, if any. And I forgot to write the E=mc2 formula in the picture but it will be needed to prove my formulas right or wrong. You'll need it in the m=E/c2 form. Enjoy. Link to comment Share on other sites More sharing options...
swansont Posted December 21, 2020 Share Posted December 21, 2020 What is F=G/c^2, and where did your equations come from? How would you test them to see if they work? Link to comment Share on other sites More sharing options...
Neptune Posted December 21, 2020 Author Share Posted December 21, 2020 F is a constant I like to call Flavio's Constant after my First name I my equations came from Physics equations that I combined and then simplified. As for testing I've only solved them mathematically to my knowledge to be real, experimentally it's up for grabs Does this help you better grasp it? I did the calculations for a visible green frequency photon. Link to comment Share on other sites More sharing options...
swansont Posted December 21, 2020 Share Posted December 21, 2020 29 minutes ago, Neptune said: F is a constant I like to call Flavio's Constant after my First name That’s bad form in physics. F is already Force, such a constant is unnecessary, and you don’t name things after yourself 29 minutes ago, Neptune said: I my equations came from Physics equations that I combined and then simplified. What equation for a photon radius depends on G? Link to comment Share on other sites More sharing options...
Neptune Posted December 21, 2020 Author Share Posted December 21, 2020 You can solve the radius of a gravitational body depending on the gravity of the surface. Of course the gravity of the surface of a photon is the gPhoton equation. That's what In this picture. My photon radius and the approach just mentioned above being equal should leave you doubtless. It's not only for green photons if that's your next question, but if you want to ask me to prove that too I will. Link to comment Share on other sites More sharing options...
joigus Posted December 21, 2020 Share Posted December 21, 2020 You are serious, then? I couldn't believe you were serious. Link to comment Share on other sites More sharing options...
Neptune Posted December 21, 2020 Author Share Posted December 21, 2020 Yes I am sincerely serious Link to comment Share on other sites More sharing options...
joigus Posted December 21, 2020 Share Posted December 21, 2020 \( F= \frac{G}{c^2} \) has units of (mass)-1x(length) Energy has units of (mass)x(length)2x(time)-2 So \( \sqrt[4]{F\times E_\text{photon}} \) has dimensions of (length)3/4x(time)-1/2. So that's a non-starter from dimensional analysis alone. Sorry, I honestly thought you were joking in the Physics section. I immediately removed the neg reps. Link to comment Share on other sites More sharing options...
swansont Posted December 21, 2020 Share Posted December 21, 2020 39 minutes ago, Neptune said: You can solve the radius of a gravitational body depending on the gravity of the surface. Of course the gravity of the surface of a photon is the gPhoton equation. That's what In this picture. My photon radius and the approach just mentioned above being equal should leave you doubtless. It's not only for green photons if that's your next question, but if you want to ask me to prove that too I will. The problem isn’t getting from one made-up equation to another, it’s tying the equation to something that’s not. Speculations rules require that you back up your conjecture. Citing one speculation to backstop another doesn’t do that. Link to comment Share on other sites More sharing options...
Neptune Posted December 21, 2020 Author Share Posted December 21, 2020 If the dimensional analysis of it was why does it still give me G when I do this? Link to comment Share on other sites More sharing options...
joigus Posted December 22, 2020 Share Posted December 22, 2020 (edited) 54 minutes ago, Neptune said: If the dimensional analysis of it was why does it still give me G when I do this? Easy, because as @swansont told you, you're going around in circles. \[ \frac{\sqrt{FE_R} \left( \sqrt[4]{FE_R} \right)^2}{\frac{E_R}{c^2}} = \left( FE_R \right)^{\frac{1}{2}+\frac{2}{4}} \frac{c^2}{E_R} =\] \[ = Fc^2 = \frac{G}{c^2}c^2 = G \] You derive guess an equation from your definition. You substitute your definition, so you get to an identity. Doesn't matter that your definition dimensionally has no relevance. And your \( g_\text{photon} \) has the funny dimensions of (length)3/2(time).1. Edited December 22, 2020 by joigus streamlining LateX Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now