Gemm94 Posted April 24, 2021 Posted April 24, 2021 Please help me the following equation, we need to calculate X relative to the other: \begin{equation} \tan{(2X-\phi_0)} = \frac{\rho\sin{\phi-a\sin{X}}}{\rho\cos{\phi}-a\cos{X}} \end{equation} Thank you very much!
Country Boy Posted April 26, 2021 Posted April 26, 2021 (edited) What does "relative to the other" mean? What "other"? [math]tan(\alpha- \beta)= \frac{tan(\alpha)- tan(\beta)}{1+ tan(\alpha)tan(\beta)}[/math] so [math]tan(2X- \phi_0)= \frac{tan(2X)- tan(\phi_0)}{1+ tan(2X)tan(\phi_0)}[/math]. By the same formula [math]tan(2X)= tan(X- (-X))= \frac{2tan(X)}{1- tan^2(X)}[/math] Edited April 26, 2021 by Country Boy 1
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