Are These the Formulas?

[captcass]

Hi folks. I finally found my formulas. Thank you, Mordred, for your early help and decent, courteous, replies.

What is happening is this:

Time evolves space, and spatial events, forward at c in the forward direction of time. Densities in space, masses, slow that evolution and their velocities are how time keeps them up with the rest of the continuum.

Since orbital velocity, V_O, = √(GM/R), the time dilation formulas for  orbital velocities are derived from the gravitational time dilation formula,

T₀ = T√1 – (2GM/Rc²), which contains the velocity formula, by substituting

V_O for GM/R, i.e.:

T₀ = T√1 – ((2/c²)(V_O)), resulting in:

V_Op = √2*√((Tc² – T₀c²)/2T)), for planetary and moon velocities, where T = 1 is the distant observer’s invariant rate of universal time, T₀ is the rate of time

 

of the coordinate point, and √2 is the gravitational acceleration factor, due to the fact that the multipliers for the planets are in the range of  Mercury =

 

1.41474412726671 and Neptune = 1.41379959891788, very close to √2 at1.4142, and what follows:

Einstein's Fundamental Metric (with the x,y,z,t,coordinates), describes the diagonal of a cube. (image in the paper).

Assigning 1 km for the length of each side, we see that the diagonal, y = √3 and the hypotenuse of a side x =

√2, and we find that using

 

V_Og = (√((Tc² – T₀c²)/2T))/((√3)/(√2)) = (√2*√((Tc² – T₀c²)/2T))/(√3), using the Sun’s surface dilation factor, gives us            us the actual galactic rotational

 

velocity of 231 km/s for the Sun.

 

Again, looking at the cube, Y is the Fundamental Direction of Evolution. The planets appear accelerated in the plane of the ecliptic, along  X, at √2. The stellar system as a whole, centered on the Sun, is also being accelerated by a factor of √2, but it is along Y, the FDE, so the planetary result is divided by √3. As in the cube, this keeps the planets in the same  plane of evolution as the Sun.

So, the equations are:

V_Op = √2*√((Tc² – T₀c²)/2T)), for planetary and moon velocities and:

V_Og = (√2*√((Tc² – T₀c²)/2T))/(√3), for galactic velocities.

Since T=1, these formulas reduce to:

V_Op = √(c² – T₀c²), for planetary and moon orbital velocities and:

V_Og = √((c² – T₀c²))/(√3), for galactic rotational velocities.

For cometary velocities, it is necessary to derive the time dilation  velocity formula from the Vis-Viva equation, which is:

V_Oc = √((2*(c² – T₀c²) – (c² – T_0αc²))

Where T₀ = the rate of time factor for “r” in the Vis-Viva equation and T_0α = the rate of time factor for a distance equal to the length of the semi-major axis, α.

Since this is the derivation for the Vis-Viva formula, it is the exact solution for any stellar system body when using the dilation gradient of the  central mass of the stellar or planetary system.

 

The Force in Time

Now that we know that √(GM/r) = √(c² – c²T₀), we can make that substitution in other equations.

Deriving the gravitational force, in Newtons, through time dilation, we use Newton’s equation: F = G(M₁m₂)/r² = (GM₁/r)*(m₂/r) = (√(c² – c²*T_o)²*(m₂/r) = ((m₂)(c² – c²T_o))/r, where T_o is the rate of time factor for the coordinate mass, m₂. Of course, the equation works in the obverse for the other mass, M₁.

As of today, 75% of the astrophysicists/astronomers in the English-speaking universities worldwide have downloaded my paper.

The latest version is at thetruecosmology.com. If you have downloaded it before, please hit "refresh" when the paper loads so you get the latest version, and not your cached version.

 

 

 

 

[pzkpfw]

It's the time cube.