qwerty Posted August 27, 2005 Posted August 27, 2005 Hi, my questions are, if you want to titrate ammonia ion NH4+ with H3PO4, firstly, the h3po4 is triptopic.. meaning it yields 3 hydrogen ions per molecule. IS THIS TRUE? secondly, the original equation is NH3 + H2O --> NH4+ + OH- Now, titrating this base with H3PO4, i believe the equation of titration would be: NH4+(aq) + 3OH-(aq) + H3PO4(aq) --> 3H2O(l) + (NH4)3PO4(aq) is (NH4)3PO4 a likely product? or would it be (nh4)2HPO4?
budullewraagh Posted August 27, 2005 Posted August 27, 2005 aqueous ammonia can be titrated with H3PO4 to yield ammonium phosphate. depending on concentrations and overall solution pH (possibly changed by presence of other acids/bases) the monobasic, dibasic and tribasic salt can be obtained
qwerty Posted August 28, 2005 Author Posted August 28, 2005 is that equation i gave above, NH4+(aq) + 3OH-(aq) + H3PO4(aq) --> 3H2O(l) + (NH4)3PO4(aq) correct?
Borek Posted August 28, 2005 Posted August 28, 2005 Only if you let the solution dry. As long as there is some water, you will have some mixture of NH4+ and HPO4(2-). Too weak base and too weak acid for anything else. For example solution which is 0.01M phosphoric acid and 0.03M ammonia (so should be perfect salt) will have pH of 8.96. Only 66.1% of ammonia will be in NH4+form. As for phosphoric acid - 1.7% H2PO4- and 98.3% HPO4(2-) (H3PO4 and PO4(3-) also present, although below 0.1% levels). BATE pH calculator rulez Best, Borek -- Chemical calculators at www.chembuddy.com pH calculation concentration conversion
Tetrahedrite Posted August 29, 2005 Posted August 29, 2005 is that equation i gave above' date=' NH4+(aq) + 3OH-(aq) + H3PO4(aq) --> 3H2O(l) + (NH4)3PO4(aq) correct?[/quote'] I think a more appropriate (simple) equation would be: 3NH3 + H3PO4 --> 3NH4+ + PO4(3-)
budullewraagh Posted August 29, 2005 Posted August 29, 2005 actually, the acid dissociation constant of HPO4-2 is 4.2 x 10^-13 whereas the acid dissociation of NH4+ is 5.7 x 10^-10. according to these figures, formation of tribasic ammonium phosphate cant be favored as seen above, because HPO4-2 is a stronger base than NH4+.
Tetrahedrite Posted August 30, 2005 Posted August 30, 2005 actually, the acid dissociation constant of HPO4-2 is 4.2 x 10^-13 whereas the acid dissociation of NH4+ is 5.7 x 10^-10. according to these figures, formation of tribasic ammonium phosphate cant be favored as seen above, because HPO4-2 is a stronger base than NH4+. This is only true if the concentration of both the ammonia and the phosphoric acid are the same. At any rate the simple equation above is more correct than the equation given by qwerty which contains two acids on the same side of the equation
budullewraagh Posted August 30, 2005 Posted August 30, 2005 variable concentration will only affect kinetics. this: 3NH3 + H3PO4 --> 3NH4+ + PO4(3-) is not completely correct because there must be an excess of NH3 to form the tribasic salt
qwerty Posted September 2, 2005 Author Posted September 2, 2005 h2so4 is an acid, what are the other acids on the same side of the equatoin? OH- is a base and isnt NH4 is a base because it breaks up the water molecule to give the OH- molecule? ehhh
budullewraagh Posted September 2, 2005 Posted September 2, 2005 NH4+ cant be a base. where are its electrons to donate? certainly not there. the pKa is 9ish, so it has acidic character. this is why ammonium salts are generally slightly acidic.
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