Trond Posted August 31, 2005 Posted August 31, 2005 Example: x = √3x+7-1 x+1 = √3x+7 (x+1)² = (√3x+7)² x²+2x+1 = 3x+7 Question: Why +2x? x²-6-x = 0 Question: Why -6-x? x = -2 OR x = 3 Question: How can you see the answer will be -2 or 3?
BigMoosie Posted August 31, 2005 Posted August 31, 2005 At first I thought you had made very strange errors in your working, would I be correct to presume that the very first line is actually this? [math]x = \sqrt{3x+7} - 1[/math] If so the working goes as follows: [math](x + 1)^2 = 3x+7[/math] [math](x + 1)(x+1) = 3x+7[/math] [math]x(x+1) + 1(x+1) = 3x+7[/math] [math]x^2 + x + x+ 1 = 3x+7[/math] [math]x^2 + 2x + 1 = 3x+7[/math] Hopefully that answers your first question. And then we subtract 3x + 7 from both sides: [math]x^2 + 2x + 1 - (3x + 7) = 3x + 7 -(3x + 7)[/math] [math]x^2 - x - 6 = 0[/math] Then factorising: [math](x-3)(x+2) = 0[/math] [math]x-3 = 0[/math] or [math]x+2 = 0[/math]
Trond Posted September 6, 2005 Author Posted September 6, 2005 Thanks for reply. Long story short, it's been many years so I'm taking lower level of math before I jump into this again. Is there a program I can use to make those symbols and print out?
Phi for All Posted September 6, 2005 Posted September 6, 2005 Is there a program I can use to make those symbols and print out?Here is a Quick LaTeX Tutorial to help you.
VikingF Posted September 6, 2005 Posted September 6, 2005 Isn't it called "irrational equations"? (I'm a Norwegian too, so I know what "irrasjonelle likninger" is.)
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now