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Posted (edited)

 In hypergeometric distribution, n= population of n elements, r = sample size, n1 = elements recognized as having some defined criteria, n2 = n - n1 =  remaining elements other than n1 . We seek the probability qk such that the sample size r contain exactly k recognized elements provided [math]k \geq 0, k \leq n_1 [/math] if n1 is smaller  or [math] k \leq r[/math] if r is smaller. In such a case the probability [math]q_k =\frac{\binom{n_1}{k}\binom{n- n_1}{r - k}}{\binom{n}{r}} \tag {1}[/math]

Now, I want to calculate n=8500, n1 =1000, r = 1000, k = 0 to 100.  Inserting these values in (1), calculation of summation is very difficult.  In such case, how can I use normal approximation to binomial distribution to find qk ?

Do you have any clue or hint?

     

Edited by Dhamnekar Win,odd

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