Dhamnekar Win,odd Posted April 27, 2022 Posted April 27, 2022 Answer to question (b) assumes Maxwell-Boltzmann statistics. But how to show that the probability of each distinguishable distribution is [math]n*(N)^r ?[/math] Why is Bose-Einstein statistics impossible here? Each distinguishable distribution have equal probability of [math]\frac{r!(n-1)!}{(n+r-1)!}[/math] under Bose-Einstein statistics.
Dhamnekar Win,odd Posted April 28, 2022 Author Posted April 28, 2022 (edited) Please read 'Answer to question (b) assumes Maxwell-Boltzmann statistics. But how to show that the probability of each distinguishable distribution is [math] \frac {1} {n*N^r} [/math] ?' What is meaning of Note given? Edited April 28, 2022 by Dhamnekar Win,odd
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