Neutral simultaneity for two frames.

[Genady]

3 minutes ago, DimaMazin said:

Teachets teached us 0/0=1

What is in Israel?

 

 

 

0/0=1 is wrong everywhere.

[TheVat]

In US we were taught zero is a rational number, which means it must have a nonzero denominator, i.e. it is 0/1.  A rational number cannot have a zero denominator.  I have have no idea what 0/0 is, but it cannot be a ratio.  

[DimaMazin]

58 minutes ago, Genady said:

0/0=1 is wrong everywhere.

Well. 0/0=unknown

Then E₁=unknown²×0=0

E₂=unknown²×0=0

[Genady]

35 minutes ago, DimaMazin said:

unknown²×0=0

No such thing.

[DimaMazin]

26 minutes ago, Genady said:

No such thing.

Well. any²×0=0

 

[Genady]

Just now, DimaMazin said:

Well. any²×0=0

 

Not any. Only numbers.

[studiot]

3 hours ago, DimaMazin said:

Teachets teached us 0/0=1

What is in Israel?

 

Consider the following

 

Let

[math]y=\frac{{{2^x}-1}}{x} [/math]

 

What is y when x = 0 ?

Clue it is not 1 it is about 0.693

Edited August 19, 2023 by studiot

[DimaMazin]

5 hours ago, Genady said:

Not any. Only numbers.

You don't know what is 0/0. Then what do you try to explain?

[Genady]

24 minutes ago, DimaMazin said:

You don't know what is 0/0. Then what do you try to explain?

Division by zero - Wikipedia

Quote

division by zero is undefined (a type of singularity). Since any number multiplied by zero is zero, the expression  is also undefined

 

[DimaMazin]

1 hour ago, Genady said:

Division by zero - Wikipedia

 

Do you think that undefined opinios of mathematicians are more useful in physics than laws of physics?

7 hours ago, studiot said:

 

Consider the following

 

Let

y=2x−1x

 

What is y when x = 0 ?

Clue it is not 1 it is about 0.693

For y=x/x

When we approach x to 0 there is no changing of the result.

[studiot]

5 hours ago, DimaMazin said:

For y=x/x

When we approach x to 0 there is no changing of the result.

What a pity you didn't simply ask how I came to my answer.

If we try to substitute x = 0 into the given expression we find

 

[math]\frac{{{2^x} - 1}}{x} \to \frac{{1 - 1}}{0} \to \frac{0}{0}[/math]

 

Which we know we cannot do.

 

But the situation is remedable as we can apply l'Hopital's rule thus

 

[math]\frac{{\frac{d}{{dx}}\left( {{2^x} - 1} \right)}}{{\frac{d}{{dx}}\left( x \right)}} = \frac{{2^x}\ln 2}{1} = \ln 2 = 0.693[/math]

 

 

Edited August 20, 2023 by studiot

[Genady]

8 hours ago, DimaMazin said:

Do you think that undefined opinios of mathematicians are more useful in physics than laws of physics?

I don't need to think so because there is no conflict between mathematics and physics. 

YOUR so-called "laws of physics" are nonsense.

[DimaMazin]

3 hours ago, Genady said:

I don't need to think so because there is no conflict between mathematics and physics. 

YOUR so-called "laws of physics" are nonsense.

Let's use conservation of momentums for correct addition of velocities

V₃×gamma₃=v₁×gamma₁+v₂×gamma₂

[Genady]

Just now, DimaMazin said:

Let's use conservation of momentums for correct addition of velocities

V₃×gamma₃=v₁×gamma₁+v₂×gamma₂

It is not a "correct addition of velocities."

[DimaMazin]

1 hour ago, Genady said:

It is not a "correct addition of velocities."

When travelers ,relative to each other , have d momentum then it is the same in any frame.

Edited August 20, 2023 by DimaMazin

[Genady]

11 minutes ago, DimaMazin said:

When travelers ,relative to each other , have d momentum then it is the same in any frame.

This statement does not make sense.

[DimaMazin]

4 minutes ago, Genady said:

This statement does not make sense.

When they have equal masses.

[Genady]

4 minutes ago, DimaMazin said:

When they have equal masses.

It needs more clarifications.

[DimaMazin]

9 hours ago, Genady said:

It needs more clarifications.

When you have got change of momentum dp then any observer,in any frame, defines  the your change of momentum as the same dp.

[Genady]

6 hours ago, DimaMazin said:

When you have got change of momentum dp then any observer,in any frame, defines  the your change of momentum as the same dp.

What does make you think so?

[DimaMazin]

On 8/21/2023 at 12:39 PM, Genady said:

What does make you think so?

A very simple  refutation of Einstein's law of addition of velocities.

[Genady]

1 minute ago, DimaMazin said:

A very simple  refutation of Einstein's law of addition of velocities.

It is called "a wishful thinking."

[studiot]

Quote

Hawking, via Moontanman

“The greatest enemy of knowledge is not ignorance, but illusion of knowledge.” — Stephen Hawking

Hawking, via Moontanman,

 

his joke in the jokes thread is rather good too.

 

[DimaMazin]

17 hours ago, Genady said:

It is called "a wishful thinking."

Yes, i mistaken.

[DimaMazin]

The Einstein's law is incorrect because we cannot use the same module of reverse velocities in two frames. 😝