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Posted
7 hours ago, Genady said:

No, any one of them. I'd start with something simple.

What experiment did Einstein present to the formula?

Posted
4 minutes ago, DimaMazin said:

What experiment did Einstein present to the formula?

The formula is a mathematical result. The question is experimental test of mathematics:

 

8 hours ago, DimaMazin said:

What experiment proves the mathematics?

 

If mathematics is correct, then the formula is correct. 

Posted
11 minutes ago, Genady said:

The formula is a mathematical result. The question is experimental test of mathematics:

 

 

If mathematics is correct, then the formula is correct. 

We consider physics and the mathematics has no relation to the physics.

Posted
Just now, DimaMazin said:

We consider physics and the mathematics has no relation to the physics.

Mathematics has relation to everything. Physics included.

Posted
42 minutes ago, Genady said:

Mathematics has relation to everything. Physics included.

Concrete mathematics was created by smoked brain. We cannot apply it anywhere.

Posted

Are you trying to win a bet with someone that you can be even more ridiculous and even more profoundly absurd than you already were in previous posts?

Posted
21 minutes ago, DimaMazin said:

Concrete mathematics was created by smoked brain. We cannot apply it anywhere.

YOU cannot apply it anywhere.

I guess, you understand Russian. This is for you:

Плохому танцору пол мешает.

Posted
3 hours ago, iNow said:

Are you trying to win a bet with someone that you can be even more ridiculous and even more profoundly absurd than you already were in previous posts?

I made correct math. Genady don't understand it because he is ortodoxal. You don't understand it because you understant no math at all.

Posted
On 8/16/2023 at 6:45 AM, iNow said:

Sick burn, bruh

My idea is so. Velocity v is between S and S' . gamma=1/(1-v2/c2)1/2.

Object travels with velocity u  in rame S. Norm of relation between distances and times is defined by gamma.

u is rate of change of distance at time in S and it is the same when S travels in S'. We should only transform it relative to distance and time of S'. Then u transforms into u/gamma. And we should add velocity  v.

u'=v-u/gamma

Einstein's velocity u' is another and therefore it changes norm of contracted and not contracted distances and times. Therefore it is incorrect.

Posted
5 hours ago, DimaMazin said:

u'=v-u/gamma

The following example proves that your formula is incorrect.

Take v=.8c, u=-.8c. Plug them into your formula. It gives,

u'=1.28c

which is faster than the speed of light!

Posted
7 minutes ago, Genady said:

The following example proves that your formula is incorrect.

Take v=.8c, u=-.8c. Plug them into your formula. It gives,

u'=1.28c

which is faster than the speed of light!

Thanks. 

Posted
On 8/16/2023 at 2:56 AM, Genady said:

YOU cannot apply it anywhere.

I guess, you understand Russian. This is for you:

Плохому танцору пол мешает.

It is exactly incorrect because it violates energy momentum law.

S' is traveling with velocity v in S. We acselerate body to S' then the body has momentum p1 and energy E1. Then we acselerate the body to v2. Then the body has momentum p and energy E . In the same time  the body has momentum p2 and energy E2 in S'.

The enegy momentum law is

E1=(p1/p)2E          E2=(p2/p)2E

Posted (edited)
24 minutes ago, Genady said:

Then how does it work if p=0?

Then pand p2=0. E=0

0/0=1

E1=12×0=0         E2=12×0=0

E is kinetic energy

Eand E are kinetic energies.

Edited by DimaMazin

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