Dr Finlay Posted September 13, 2005 Posted September 13, 2005 This is a question from my school text book:- The line y = 3x - 5 meets the x-axis at the point M. The line y = -2/3x + 2/3 meets the y axis at the point N. Find the equation of the line joining the points M and N. Write your answer in the form ax + by + c = 0. For point M i got the coordinate (5/3, 0) and for point N (0, 2/3) I next worked out the gradient of the line connecting M and N to be -2/5 and tried using y - y1 = m(x - x1) to get the equation for the line eventually getting to 6x - 15y - 3 = 0, however the book lists the answer as 6x + 15y - 10 = 0. Is my answer the correct answer and the book's answer wrong, or did i mess up in my working out somewhere? I've been pondering on it for a while and cant see how the book got its answer. Thanks for any help Rob
Ducky Havok Posted September 13, 2005 Posted September 13, 2005 Check your work again because I worked it out and got the books answer. But don't worry to much, a lot of the time the book can be wrong
DQW Posted September 13, 2005 Posted September 13, 2005 The book's answer is correct. So are your steps up to everything that you've shown. (points are correct; slope is correct) Perhaps you made a mistake substituting (x1,y1) in the final equation. Which point did you use - M or N ? I suggest you recheck this last bit of working, or show what you did.
Dr Finlay Posted September 13, 2005 Author Posted September 13, 2005 y - 2/3 = -2/5 x 5/3 -5y + 2/3 = -5/3 - 2x -15y + 2 = -5 -6x 6x -15y + 7 = 0
Mobius Posted September 13, 2005 Posted September 13, 2005 I think I see your problem. y-y1=m(x-x1) You have chosen the point (0,2/3) therefore x1 = 0 y1=2/3 That will give the right answer
Ducky Havok Posted September 13, 2005 Posted September 13, 2005 Whatever you just did really is confusing. Here's how I did it: One of your points is (0, 2/3) so you know your y intercept is 2/3. The slope -2/5 is right, so I just plugged it into the equation y=mx+b and got: y=-2x/5+2/3 Then multiply both sides by 15 and get: 15y=-6x+10 Then just solve for zero, 6x+15y-10=0 Edit:Well Mobius found your error and explained it before me, oh well. At least I showed you another method to do it.
Dr Finlay Posted September 13, 2005 Author Posted September 13, 2005 Cheers guys, see where i went wrong now. Having just had a rather long break from maths over the summer months my brain is half asleep most of the time.
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