RK4 Posted September 19, 2005 Posted September 19, 2005 Use Bertrand's Postulate to show that every positive integer n with n >= 7 is the sum of distinct primes. I know that Bertrand's Postulate states that for every positive integer n with n > 1, there is a prime p such that n < p < 2n. So, in our case since n >= 7 > 1 we can deduce that n < p < 2n That's pretty much all I can say looking at the postulate itself. What else?
matt grime Posted September 19, 2005 Posted September 19, 2005 Suppose for a minimal counter example. N, then there is a prime in the ragen N/2 to N, call it p, now think a little to get a contradiction,
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