Alferd Posted May 21, 2023 Posted May 21, 2023 If I want to reflect sunlight by using concave mirror which had 10cm*10cm size, how much the focal length of concave mirror should be designed in order to obtain 1.5 times light reflection size which had 15cm*15cm?
Alysdexic Posted June 21, 2023 Posted June 21, 2023 (edited) 1/f = 1/o + 1/i f = focal length o = object distance (10cm) i = image distance (15cm) Plug in the known values. 1/f = 1/10cm + 1/15cm . . . (You do the rest.) Edited June 21, 2023 by Alysdexic -2
Genady Posted June 21, 2023 Posted June 21, 2023 3 minutes ago, Alysdexic said: 1/f = 1/o + 1/i f = focal length o = object distance (10cm) i = image distance (15cm) Plug in the known values. 1/f = 1/10cm + 1/15cm . . . (You do the rest.) The OP did not say anything about object/image distance. Rather about mirror/reflection size.
Alysdexic Posted June 21, 2023 Posted June 21, 2023 9 minutes ago, Genady said: The OP did not say anything about object/image distance. Rather about mirror/reflection size. So why don't you answer them instead of replying to me? OP: 10cm x 10cm 15cm x 15cm (1.5 times larger) f = r^2 / 4s f = focal length r = radius of the mirror / 10cm (half the mirror's diameter) s = enlargement ratio / 1.5 (50% enlargement) f = (10cm)^2 / 4(1.5), etc. -1
John Cuthber Posted June 21, 2023 Posted June 21, 2023 4 minutes ago, Alysdexic said: So why don't you answer them Because it is impossible to give a meaningful answer to the OP's question. 4 minutes ago, Alysdexic said: instead of replying to me? Because it is potentially helpful to you if we point out that your reply, while well intended, was wrong. 2
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