Oscillatory nuclear fusion hypothesis

[Dmi3007]

4 hours ago, exchemist said:

What hydrogen pressure gradient?

But also If a syringe with deuterium is attached to the blunt end of a positively charged needle and a certain excess concentration of deuterons is created in the needle. then near the tip of the needle a certain amount of them will appear, held by the forces of electric attraction.

The situation may be reversed. On the one hand, the negatively charged needle is stucked into the SDM; on the other side of the SDM is a proton exchange membrane that supplies deuterons from pressurized deuterium. A dense cloud of deuterons is formed on the membrane opposite the needle, the distances between which can be sufficient for nuclear fusion.

Edited August 23, 2023 by Dmi3007

[swansont]

1 hour ago, Dmi3007 said:

In the case under consideration, deuterons are held by electrons. The interaction of nuclei and electrons is a quantum mechanical process. This interaction is stable contrary to Eamshaw's theorem, since it does not work there. 
Electrons can be stably smeared around nuclei contrary to this theorem.
Theorem will not work for quants.

What are you talking about? Electrons do not immobilize the nucleus. The whole atom is free to move. You were talking about creating the electrostatic field with a composite dielectric. How did we get from that to the electron in deuterium? (which has no electron when it’s ionized, as you said it was)

 

[Dmi3007]

28 minutes ago, swansont said:

What are you talking about? Electrons do not immobilize the nucleus. The whole atom is free to move. You were talking about creating the electrostatic field with a composite dielectric. How did we get from that to the electron in deuterium? (which has no electron when it’s ionized, as you said it was)

Are we talking about quants? How can this theorem be applied here?

[swansont]

4 minutes ago, Dmi3007 said:

Are we talking about quants? How can this theorem be applied here?

This is your proposal. Which uses classical equations to describe the electric field you are generating. One might think that it’s a classical problem.

[Dmi3007]

13 hours ago, swansont said:

This is your proposal. Which uses classical equations to describe the electric field you are generating. One might think that it’s a classical problem.

No, with all due respect to you, if we are solving a task with quants, this is a quantum mechanic task, and Earnshaw's theorem does not work there.

Edited August 24, 2023 by Dmi3007

[swansont]

9 hours ago, Dmi3007 said:

No, with all due respect to you, if we are solving a task with quants, this is a quantum mechanic task, and Earnshaw's theorem does not work there.

But you have not solved anything - particularly the immobilization of the deuteron - with quantum mechanics. 

[Dmi3007]

30 minutes ago, swansont said:

But you have not solved anything - particularly the immobilization of the deuteron - with quantum mechanics. 

Why? I described deuteron behaviour in the attached video. If we have some exceed of their concentration, they are oscillating near the equilibrium position in the first approaching. But of course the real behaviour is more complicated as they have wave properties too. 

But I think that the experiment with negative charged needle inside SDM and the supplying of deuterons to the tip through the PEM could be more lucky and simple. 

Edited August 24, 2023 by Dmi3007

[Dmi3007]

2 hours ago, swansont said:

But you have not solved anything - particularly the immobilization of the deuteron - with quantum mechanics. 

I think I understand the probable mistake Pd could start to be semiconductor al the exceeding hydrogen concentration inside. The critical larval is D/Pd = 0,5

Edited August 24, 2023 by Dmi3007

[exchemist]

On 8/23/2023 at 2:20 PM, Dmi3007 said:

But also If a syringe with deuterium is attached to the blunt end of a positively charged needle and a certain excess concentration of deuterons is created in the needle. then near the tip of the needle a certain amount of them will appear, held by the forces of electric attraction.

The situation may be reversed. On the one hand, the negatively charged needle is stucked into the SDM; on the other side of the SDM is a proton exchange membrane that supplies deuterons from pressurized deuterium. A dense cloud of deuterons is formed on the membrane opposite the needle, the distances between which can be sufficient for nuclear fusion.

Are you seriously suggesting the pressure of a syringe could be enough to force deuterium nuclei together sufficiently to cause fusion? That is insane.

[Dmi3007]

12 hours ago, exchemist said:

Are you seriously suggesting the pressure of a syringe could be enough to force deuterium nuclei together sufficiently to cause fusion? That is insane.

No definetly like you tell.  I think, the temperature or pressure may be reason for deuterons to go away from the needle. But if the needle have a positive charge the way out is the needle tip. Electric forces (attraction to the negative charges inside the tip will hold the deuterons and SDM will make deuterons density critical for fusion.

Why insane? Did you measure the energy of the pressure or temperature? Lets now use this energy not for all deuterons in the needle, but only for deuterons near the tip. This is very small quantity (much-much less than 1 Gramm). And this is very huge energy for this quantity to make it closer for fusion distances.