grayson Posted November 11, 2023 Share Posted November 11, 2023 V1 = H0 + V0 / š This is my equation for the increasing size of a closed universe. It is explaining that V1, or the velocity of the universe, is equal to V0, or the last velocity of the universe per second per megaparsec. The H0Ā is the Hubble constant, and the expansion of the universe. Gamma, is the Lorentz factor which is used in incorporating special relativity into the equation and using the laws of special relativity. I am open to criticism.Ā Remember, this cannot be used on an open and infinite universe, it is only for a closed universe, which we do not know if our universe is or not. Link to comment Share on other sites More sharing options...
Halc Posted November 11, 2023 Share Posted November 11, 2023 1 hour ago, grayson said: It is explaining that V1, or the velocity of the universe The velocity of the universe would be the change in its position relative to something that isn't the universe. It really makes no sense for a universe to have a velocity.= 1 hour ago, grayson said: or the last velocity of the universe per second per megaparsec Velocity per second per megaparsec would be something like v/t/d (velocity, time, distance) which is d/t / t / d which is 1/tĀ², something with different units than velocity at least. As for special relativity, that only applies to flat Minkowskian spacetime with zero energy and mass anywhere. For this reason, it is simply inapplicable to our universe except locally. Your equation adds values of different units, which makes it meaningless. You can't add meters to Pascals, and (in your case), you can't add H (units 1/t) to V/Ī³ (units d/t) Another criticism:Ā Ī³ is the Lorentz factor of what exactly?Ā It should be the factor for some speed, but "the Lorentz factor which is used in incorporating special relativity into the equation and using the laws of special relativity" is just a word salad. Link to comment Share on other sites More sharing options...
grayson Posted November 11, 2023 Author Share Posted November 11, 2023 (V1 = H0 + V0) / š I got my order of operations wrong, does this work better? Ā 5 minutes ago, Halc said: The velocity of the universe would be the change in its position relative to something that isn't the universe. It really makes no sense for a universe to have a velocity.= Velocity per second per megaparsec would be something like v/t/d (velocity, time, distance) which is d/t / t / d which is 1/tĀ², something with different units than velocity at least. As for special relativity, that only applies to flat Minkowskian spacetime with zero energy and mass anywhere. For this reason, it is simply inapplicable to our universe except locally. Your equation adds values of different units, which makes it meaningless. You can't add meters to Pascals, and (in your case), you can't add H (units 1/t) to V/Ī³ (units d/t) Another criticism:Ā Ī³ is the Lorentz factor of what exactly?Ā It should be the factor for some speed, but "the Lorentz factor which is used in incorporating special relativity into the equation and using the laws of special relativity" is just a word salad. Hold on, I think I got this now... V1 = (227 * 10-18Ā +Ā V0)/ š Which happens every second Ā or this V1 = ((227e-18 + V0) / š) / s Never mind, loopholes. Scratch that V1 = ((227e-18 + V0) / š) * s Do this instead Link to comment Share on other sites More sharing options...
Bufofrog Posted November 11, 2023 Share Posted November 11, 2023 2 hours ago, grayson said: This is my equation for the increasing size of a closed universe. The recession velocity of the farthest galaxies exceed the speed of light so your equation must be wrong since your equation 'blows-up" if v=c. Link to comment Share on other sites More sharing options...
grayson Posted November 11, 2023 Author Share Posted November 11, 2023 19 minutes ago, Bufofrog said: The recession velocity of the farthest galaxies exceed the speed of light so your equation must be wrong since your equation 'blows-up" if v=c. When you are talking aboutĀ v,Ā are you talking aboutĀ V, or vĀ (Volume or velocity). Because if v is velocity, than the only time v shows up is in theĀ LorentzĀ factor, which is the speed of the observer. The 227e-18 is just an approximation of the speed of the expansion of the universe in m/s (meters per second). I don't know. I am up for criticismĀ Link to comment Share on other sites More sharing options...
Bufofrog Posted November 11, 2023 Share Posted November 11, 2023 9 hours ago, grayson said: When you are talking aboutĀ v,Ā are you talking aboutĀ V, or vĀ (Volume or velocity). Every use of 'v' in your equation is velocity so I am not sure why you think I would be talking about a volume. 9 hours ago, grayson said: Because if v is velocity, than the only time v shows up is in theĀ LorentzĀ factor, which is the speed of the observer Did you forget that V1 and V2 are also velocities?Ā When you say "speed of the observer", what is the speed is relative to? Link to comment Share on other sites More sharing options...
grayson Posted November 11, 2023 Author Share Posted November 11, 2023 3 hours ago, Bufofrog said: Every use of 'v' in your equation is velocity so I am not sure why you think I would be talking about a volume. Did you forget that V1 and V2 are also velocities?Ā When you say "speed of the observer", what is the speed is relative to? Hold on, I thought that V was volume. Anyways, I can change it. m1= ((227e-18 + m0) / š) * s When I say "Speed of the observer" I mean it is relative to the universe. Basically, why I addedĀ šĀ into there is because of length contraction. Because of length contraction, the universe should appear smaller to you, or at least things should appear closer to you. So when I say that, I mean relative to the universe's size, or just the universe as a whole. Hold on... I looked at the equations and V should be volume. Unless you do m (meters) but m is mass so idk Link to comment Share on other sites More sharing options...
swansont Posted November 11, 2023 Share Posted November 11, 2023 26 minutes ago, grayson said: Hold on, I thought that V was volume You clearly identify it as velocity in your first post Link to comment Share on other sites More sharing options...
grayson Posted November 11, 2023 Author Share Posted November 11, 2023 7 minutes ago, swansont said: You clearly identify it as velocity in your first post V1 = ((227e-18 + V0) / š) * sĀ This is my equation for the increasingĀ VolumeĀ of the universe.Ā V1Ā is theĀ Current VolumeĀ of the universe.Ā V0Ā is theĀ Last VolumeĀ of the universe. 227e-18Ā is the approximation of the Hubble Constant in m/s.Ā šĀ is the Lorentz factor. This incorporates things like length contraction.Ā sĀ is the number of seconds. My brain did not brain, I am sorry. And I have improved it again V1 = ((227e-18 + V0) * s) / š Link to comment Share on other sites More sharing options...
Bufofrog Posted November 11, 2023 Share Posted November 11, 2023 4 hours ago, grayson said: My brain did not brain, I am sorry. And I have improved it again V1 = ((227e-18 + V0) * s) / š You haven't improved anything your just spouting random WAGs that pop into your head.Ā It's just a waste of time, good bye. Link to comment Share on other sites More sharing options...
grayson Posted November 11, 2023 Author Share Posted November 11, 2023 10 minutes ago, Bufofrog said: You haven't improved anything your just spouting random WAGs that pop into your head.Ā It's just a waste of time, good bye. okay bye Link to comment Share on other sites More sharing options...
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