dharvin Posted October 20, 2005 Posted October 20, 2005 as most of us know the conventional rail gun uses 2 rails and an armature to complete the circuit causing the 2 rails to repel and shoot the armature at very high velocities. whati want to know is why thishappend. the force is applied perpendicular to the rails and not parallel to it. why would a force that is acting perpendicular be able to force out the armature at such speeds. :confused:
[Tycho?] Posted October 22, 2005 Posted October 22, 2005 as most of us know the conventional rail gun uses 2 rails and an armature to complete the circuit causing the 2 rails to repel and shoot the armature at very high velocities. whati want to know is why thishappend. the force is applied perpendicular to the rails and not parallel to it. why would a force that is acting perpendicular be able to force out the armature at such speeds. :confused: Step one: use more readable grammar. Step two: use google. there are hundreds of railgun sites out there.
raptor Posted September 15, 2006 Posted September 15, 2006 as most of us know the conventional rail gun uses 2 rails and an armature to complete the circuit causing the 2 rails to repel and shoot the armature at very high velocities. whati want to know is why thishappend. the force is applied perpendicular to the rails and not parallel to it. why would a force that is acting perpendicular be able to force out the armature at such speeds. :confused: The forces on the rails are perpendicular, but the current also travels through the projectile. The field from the two rails creates a force on the projectile parallel to the rails. (If you don't know this already by now)
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