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Posted

Here's problem I need help on. It relies mainly on one's intuition and intelligence. Can anone hlep me out and give a full, good explanation?

 

Every number can be represented in the standard form such as [math]\frac{100}{3} = 3.33 * 10^1[/math]. In this form the number [math]x = a * 10^N[/math], where [math]1<a<10[/math], while N is an integer exponent. Find the standard form for [math]x = 1234^1234[/math]. Include only three leading decimals in your answer, as in the previous example.

Posted

did you mean [imath] 1234^{1234} ? [/imath]

 

edit: you need a { and } around the exponent, or it'll only read the first number.

Posted
Do you have an explanation?

 

[math]1234^{1234}=10^{x}[/math]

 

[math]1234(\log(1234))=x[/math]

 

[math]1234(\log(1234)) = 3814.6829070663730305378590465079...[/math]

 

[math]1234^{1234} = (10^{3814})(10^{.6829070663730305378590465079...})[/math]

 

[math]10^{.6829070663730305378590465079...} = 4.8184467781382543701667186035719...[/math]

 

[math]1234^{1234} = 4.8184467781382543701667186035719... * 10^{3814}[/math]

 

Sorry about the large amount of digits, I'm sort of paranoid about inaccurate decimal representations, but I was too tired to figure out a probably obvious exact form.

 

But anyway, hope this helps.

Posted

Yea I was thinking the same method and got the same answer. I was hoping for a more systematic and exact way of figuring it out though. But thnx anyway :D

  • 2 weeks later...

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