Atomic Disintegration using slow electrons

[Conceptual]

If we look at the atoms the orbtial arrangment of electrons is not simple a spherical. This implies that the nucleur protons are not just in some average random state. The distinct orbital variety suggests the nuclear protons forming their own distinct orbtial variety. This would allow magnetic addtion within the nucleus leading to fancier electron orbitals.

 

Based on this theory, if one was to add many addtional electrons to an atom its should have an impact on the orbtial configuration of protons within the nucleus. Enough addtional orbital electrons should kick the protons into higher nuclear orbital states and maybe cause fission.

 

Theoretically, one way one might create atomic states like -5 or -6 is with protons. Essentially, one creates a three layered atom. The protons in the center, the electrons in orbitals, and hydrogen protons/electrons in pseudo-orbitals above this.

[[Tycho?]]

If we look at the atoms the orbtial arrangment of electrons is not simple a spherical. This implies that the nucleur protons are not just in some average random state. The distinct orbital variety suggests the nuclear protons forming their own distinct orbtial variety. This would allow magnetic addtion within the nucleus leading to fancier electron orbitals.

 

Why do non spherical orbits suggest this? Determining electron orbitals is done by (now correct me if I'm wrong here) solving Shrodingers wave equation. This equation has nothing to do with proton orbitals that I know of.

[Conceptual]

If one looks at the protons in a nucleus if the motion began as random, the charge repulsion would want the protons to exist on the surface of the nucleus so they can maximize separation. But any motion will set up magnetic fields which will also need to lower potential. This might impy bands of opposite direction or spin protons so they can add magnetically. This magnetic attraction would cause electrostatic repulsion. If we add the neutrons to the mix, these can act as electrostatic shields that also get in the way of the motion needed for magnetic additions.

 

The electrons sort of have the same problem. Charge repulsion would like to repel into a Bohr atom, while magnetic addition would like to attract. To this are added the EM forces stemming from the nucleus. The orbitals that result is the optimum balance between all the forces. The nucleus sees reflected EM forces coming from these very standandized electron orbital configurations thereby influencing its own EM optimization. If electron orbitals were more random or all spherical then random would make sense for the nucleus but very definitive electron orbital shapes implies the whole system trying to minimize EM potential. This suggests proton type orbtial configurations.

[LazerFazer]

From what I know, within the nucleus theres also the Strong nuclear force that holds the protons together. Also, a Neutron is essentially a proton and an electron fused into one particle, and so it has partial-dipoles, thereby providing even more possibilites for arrangements within the nucleus. And also, I believe the size of the overall atom is some orders of magnitude greater than the size of the nucleus, and thus the electrostatic forces originating from proton-electron interactions would be negligable with respect to the nuclear forces within the nucleus.

 

Cheers,

LF

[Conceptual]

I agree that the nuclear forces are much stronger than the EM forces. The nuclear forces contains the protons of the nucleus within a small box. But even in this small box, the protons will still have charge and magnetism due to motion. The optimization of the nuclear EM forces should create something simlar to electron orbitals. . Proton orbitals probably contain a similar degree of freedom but within the confined of certains positions within space.

 

The observation that protons never fuse without neutrons and vice versa implies that maybe the electrons fused to the neutrons move around the nucleus and may be responsible for the strong nuclear force. These are not normal electrons but electrons with no negative charge loosely bonded to protons also without positive charge.