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Posted

I did the first part but then i have no clue on how to start the other.. here's the question:

 

The reaction occurs at a temperature of 29.0 degress celsius and a pressure of 110kPa. Calculate the volume of gas that would produce if 720 mL of 1.35M sulfuric acid and 55.0g of zinc is used.

H2SO4 + Zn --> ZnSO4 + H2

n=(1.35M)(0.72L) n= 55.0/65.38

n=0.972 mol n= 0.841 mol

 

V= nRT/P

V= (0.841*8.314*302.15) \ 110

V= 19.2L

 

question b: When the reaction is part "a" occurs, 10.7 ml of water are produced. Calculate the percent error...

 

i'm not sure how i can get water..

Posted

Unless instead of H2SO4+Zn-->ZnSO4+H2 you get H2SO4+Zn-->ZnSO3+H2O.

 

But don't see how that would be possible, since they give you the reaction itself.

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