ecoli Posted October 26, 2005 Posted October 26, 2005 For my chem lab, we have to do calculations based off Nerns's law. [math] E = E^{0} - \frac{RT}{F}ln [H^{+}] [/math] The question... From the Nernst equation as it applies to the pH electrode, calculate the difference in pH corresponding to a difference in voltage of 0.1 mV (0.0001 V) at 20 C Isn't this question missing information? such as E, since you need to solve for ln [H+]... am I right?
tash =) Posted October 27, 2005 Posted October 27, 2005 I'm guessing, but wouldn't E be 0.1mV and E0 be zero?
LazerFazer Posted October 27, 2005 Posted October 27, 2005 Couldn't it be re-arranged to read: [math] E - E^{0} = - \frac{RT}{F}ln [H^{+}] [/math] and since [math] \Delta E = E - E^{0} = 0.1mV [/math] you should be able to solve it. cheers, LF
ecoli Posted October 29, 2005 Author Posted October 29, 2005 Couldn't it be re-arranged to read: [math] E - E^{0} = - \frac{RT}{F}ln [H^{+}] [/math] and since [math] \Delta E = E - E^{0} = 0.1mV [/math] you should be able to solve it. cheers' date=' LF[/quote'] yeah, that's it. I kinda figured that out after I posted this question, but thanks for the help anyways. The problem was, the lab that I got this equation from wasn't very clear on defining the variables. Thanks guys.
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