fallen_6666 Posted November 5, 2005 Posted November 5, 2005 Could someone help me with this question? The base of an isosceles triangle is 6 m. The other two sides are both increasing at 4m/s. Find the rate of increase of the area of the triangle when these sides are 5 m.
BigMoosie Posted November 5, 2005 Posted November 5, 2005 My answer is [math]15m^2s^{-1}[/math]: Base = 6 Side = 4t Height = [math]\sqrt{16t^2-9}[/math] Area = [math]f(t) = 3 (16t^2-9)^{0.5}[/math] [math]f'(t) = 48t ( 16t^2 - 9)^{-0.5}[/math] f'(1.25) = 15
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