aj47 Posted November 15, 2005 Share Posted November 15, 2005 If a chemical reaction has an order of zero it means the reaction rate can be independant of temperature. This got me thinking and the only reactions i could think of that this was true for was radioactive decay. What I don't understand is how the rate of a chemical reaction can stay constant under different temperatures. Surely all molecules gain kinetic energy from heat so therefore all reactions are speeded up by an increase of temperature. Can someone explain this to me as i'm sure i'm missing out something really fundemental. thanks. Link to comment Share on other sites More sharing options...
woelen Posted November 15, 2005 Share Posted November 15, 2005 In fact, all chemical reactions depend on temperature. This also is true for nuclear reactions, but for them, temperature sensitivity is on a totally different temperature scale. At ordinary temperatures (up to thousands of degrees), the nuclei are shielded effectively and then nuclear reactions are not affected. But at tens of millions or hundreds of millions of degrees there certainly is a dependence on temperature, just as there is in the range of hundreds of Kelvin for ordinary chemical reactions. Link to comment Share on other sites More sharing options...
aj47 Posted November 15, 2005 Author Share Posted November 15, 2005 So using 0 as the rate order is just an approximation? Link to comment Share on other sites More sharing options...
some nerd Posted November 15, 2005 Share Posted November 15, 2005 rate of reaction zero means independent of concentration. In that case, rate of reaction is proportional to rate constant which depends upon temperature. Link to comment Share on other sites More sharing options...
aj47 Posted November 15, 2005 Author Share Posted November 15, 2005 ah ok thanks, so no Chemical reactions rate is completly independant of temperature, right? Link to comment Share on other sites More sharing options...
5614 Posted November 15, 2005 Share Posted November 15, 2005 Correct. Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now