dttom Posted November 17, 2005 Share Posted November 17, 2005 http://www2.hkedcity.net/sch_files/a/kst/kst-07110/photo_album/200511/204962/507977820.JPG Addition: AD=e Anyone can help me with the above question please? P.s. If it's not shown immediately, please refresh it again. Link to comment Share on other sites More sharing options...
woelen Posted November 17, 2005 Share Posted November 17, 2005 The problem is not clear to me. Which parameter is varied, what is kept constant? Link to comment Share on other sites More sharing options...
dttom Posted November 18, 2005 Author Share Posted November 18, 2005 e,a, and b is variables; a+b=45 degree 0<=(a)<=45 Link to comment Share on other sites More sharing options...
cosine Posted November 18, 2005 Share Posted November 18, 2005 e' date='a, and b is variables;a+b=45 degree 0<=(a)<=45[/quote'] Where is e? Link to comment Share on other sites More sharing options...
dttom Posted November 19, 2005 Author Share Posted November 19, 2005 Where is e? Addition: AD=e AD=e Link to comment Share on other sites More sharing options...
uncool Posted November 19, 2005 Share Posted November 19, 2005 You want the greatest possible value of AB*AC for this, because Area = AB*AC * sin(A)/2 AB = e cos(a) AC = e cos(45-a) AB*AC = e^2*cos(a)cos(45-a) AB*AC*sin(A)/2 = e^2*cos(a)cos(45-a)sqrt(2)/4 The maximum is when a = 45 - a, or a = 22.5. e^2*cos(22.5)^2*sqrt(2)/4 = e^2*(cos(45)+1)*sqrt(2)/8 = e^2*(1 + sqrt(2))/8 =Uncool= Link to comment Share on other sites More sharing options...
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