dttom Posted November 17, 2005 Posted November 17, 2005 http://www2.hkedcity.net/sch_files/a/kst/kst-07110/photo_album/200511/204962/507977820.JPG Addition: AD=e Anyone can help me with the above question please? P.s. If it's not shown immediately, please refresh it again.
woelen Posted November 17, 2005 Posted November 17, 2005 The problem is not clear to me. Which parameter is varied, what is kept constant?
dttom Posted November 18, 2005 Author Posted November 18, 2005 e,a, and b is variables; a+b=45 degree 0<=(a)<=45
cosine Posted November 18, 2005 Posted November 18, 2005 e' date='a, and b is variables;a+b=45 degree 0<=(a)<=45[/quote'] Where is e?
uncool Posted November 19, 2005 Posted November 19, 2005 You want the greatest possible value of AB*AC for this, because Area = AB*AC * sin(A)/2 AB = e cos(a) AC = e cos(45-a) AB*AC = e^2*cos(a)cos(45-a) AB*AC*sin(A)/2 = e^2*cos(a)cos(45-a)sqrt(2)/4 The maximum is when a = 45 - a, or a = 22.5. e^2*cos(22.5)^2*sqrt(2)/4 = e^2*(cos(45)+1)*sqrt(2)/8 = e^2*(1 + sqrt(2))/8 =Uncool=
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