MattC Posted November 18, 2005 Posted November 18, 2005 When an Alkyne reacts with H2 gas over a Lindlar catalyst, the reaction stops (according to what I have read, and what my professor has said) at the alkene - it does not proceed to the alkane, whereas with a catalyist like PtO2, it will reduce the element all the way down to an alkane (at least, in some cases, as I understand it). Is the difference in the mechanism the electophilic nature of the catalyst? Is a Lindlar catalyst electrophilic enough to attract a triple bond, but not enough to lock onto a double bond? The sources I have read talk about "poisoning" the catalyst, and this confuses me. Is it a different catalyst (a "weakened" palladium?) that nevertheless acts as a catalyst should (and is not changed at all in the process), or is something happening to the catalyist itself, reducing it's ability to function? The latter is how I have heard it described, but I suspect I may have misunderstood. Thank you in advance for any help!
insane_alien Posted November 19, 2005 Posted November 19, 2005 When a catalyst is poisoned it usually means something has strongly bonded to the surface/active sites and therefore the reactants cannot be adsorbed and therefore the desired reaction cannot be catalysed. Poisoning materials usually include heavy metals like lead
MattC Posted November 20, 2005 Author Posted November 20, 2005 I am not sure, but I think the lindlar catalyst mechanism may be something else. Otherwise, using H2 gas and a lindlar catalyst on an alkyne would result in a combination of alkenes and alkanes; supposidely it results in alkenes, which makes me think that the catalyst works well on triple bonds, but not double bonds.
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