Computation of Function

[Primarygun]

Given that f(x)=x+sinx

f(pi)=?

I saw many textbooks say f(pi)=pi

But isn't it f(pi)=1/2?

[matt grime]

what do you think sin(pi) is? Or am I missing some joke/pun here?

[Dave]

None that I know of.

 

Surely you must be able to see that [imath]f(\pi) = \pi + \sin\pi[/imath]. Since [imath]\sin\pi = 0[/imath], clearly [imath]f(\pi) = \pi[/imath].

[softdragonz]

Given that f(x)=x+sinx

 

Hey .... If you can't get the answer, change the question

 

f(x) = (x/2) +sin(x)

 

Teee heee .... happy now!

 

The function given by YOU is continuous in and around PI, so, as our friend did it, you just have to substitute PI giving the result to be PI

[Primarygun]

The function given by YOU is continuous in and around PI, so, as our friend did it, you just have to substitute PI giving the result to be PI

But isn't the answer = pi radian?

[matt grime]

Only if you think that your dealing with angles and can't mix units, but since this isnt' physics that has no bearing on anything.

[Primarygun]

OK. It is the same as the notation of sin pi =0

Thanks

But what if f(x)=x+cosx

f(pi)=pi radian-1

So shall we leave the answer in this form or

(pi-1)

[matt grime]

it's maths, not physics, the answer is pi-1, not pi^c -1

 

pi is just a number.