Miseria_ Posted September 15, 2003 Posted September 15, 2003 Okay, me being me, I've forgotten the major amount of physics I learnt, in particular, specific heat capacity. so, it would be agreat help if someone could give me some means of working this out. Calculate the thermal energy required to convert 5 kg of ice at 0 degrees celsius to steam at 100 degrees celsius. (specific heat capacity © of ice = C of steam = 2100 J\Kg\K, specific heat capacity © of water = 4200 J\Kg\K, Latent heat of vapourisation = 2.3 X 10^6 J\Kg, Latent heat of fusion = 3.3 X 10^5 J\Kg thanks...
neo_maya Posted October 21, 2003 Posted October 21, 2003 Miseria_ said in post #1 :Okay, me being me, I've forgotten the major amount of physics I learnt, in particular, specific heat capacity. so, it would be agreat help if someone could give me some means of working this out. Calculate the thermal energy required to convert 5 kg of ice at 0 degrees celsius to steam at 100 degrees celsius. (specific heat capacity © of ice = C of steam = 2100 J\Kg\K, specific heat capacity © of water = 4200 J\Kg\K, Latent heat of vapourisation = 2.3 X 10^6 J\Kg, Latent heat of fusion = 3.3 X 10^5 J\Kg thanks... I think this is how it is done : _______________________ T.E to convert ice at 0'C to water at 0'C = mlf T.E to convert water at 0'C to water at 100'C = mS d :theta: T.E to convert water at 100'C to steam at 100'C = mlv T.E = mlf + mS d :theta: + mlv = 15.25 * 106 J _______________________________________________ lf = Latent heat of fusion = 3.3 X 10^5 J/Kg S = C of Water J/Kg/K lv = Latent heat of vaporisation = 3.3 X 10^6 J/Kg Don't know the function of - specific heat capacity © of ice = C of steam = 2100 J\Kg\K I'm sure there's a mistake somewhere.
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