Ferdinand Posted January 17, 2006 Posted January 17, 2006 Tom is a very large fellow, who is also a fishmonger. What does he weigh?
ski_power Posted January 17, 2006 Posted January 17, 2006 that was sooo funny... he weighs fish. How about this: consider, Mass of Tom=m Mass of Earth=M Newton's Gravitational constant=G Acceleration due to gravity=g Radius of Earth=R We know, F α Mm/R^2 F=GMm/R^2 GM=F(R^2)/m where F/m=g therefore, GM=gR^2 Let Tom be at a height h from the surface of the earth, GM=(g*)(R+h)^2 g*=Gravity at height h above earth's surface. Therefore weight of Tom W, W=(g*)(m) Final answer W= (g*)(m) Now considering Tom moving at a velocity v, where v is not neglible compared to the speed of light c. We know m0= (I'm getting bored now, anybody care to complete it?)
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