integral pumping liquid question<-need help

[caseclosed]

Your town has decided to drill a well to increase its water supply. As the town engineer, you have determined that a water tower will be necessary to provide the pressure needed for distribution, and you have designed the system shown below. The water is to be pumped from a 300-ft well through a vertical 4-in. pipe into the base of a cylindrical tank 20ft in diameter and 25 ft high. The base of the tank will be 60 ft above ground. The pump is a 3-hp pump, rated at 1650 ft*lb/sec. How long will it take to fill the tank the first time? (Include the time it takes to fill the pipe) (62.5 lb = 1 ft^3)

 

I tried to do them separtely then add the work to fill the pip and tank up.

for the pipe I got 4*pi*62.5*(360y-y^2/2) from the interval 0 to 360

for the tank I got 100*pi*62.5*(25y-y^2/2) from interval 0 to 25

 

at the end I get like 9 hours to fill the whole thing which must be wrong. please help me, I think I probally did the distance or the interval wrong but how...

 

once again, this is not homework (had to post here cause people keep saying that)

[Connor]

please don't duplicate a thread

[caseclosed]

umm, where am I suppose to post if the people in analysis calculus telling me to post here and now I get don't double post.