Nupur Posted January 19, 2006 Posted January 19, 2006 Hi, i hav a problem which i am unable to solve. it is from the chapter on trigonometry here goes: A vertical rod is fixed in a horizontal rectangular field ABCD. The angular elevations of its top from A, B, C and D are alpha, beta, gamma and delta respectively. Show that: cot^2 alpha - cot^2 beta=cot^2 delta - cot^2 gamma plzz help me with this and post the solution as soon as possible
grayfalcon89 Posted January 20, 2006 Posted January 20, 2006 I'm guessing since angle AB are supplementary and you have cos x = - cos (180-x), you can probably brute force to get the desired expression. Not sure about it though. Haven't worked the whole problem out.
EvoN1020v Posted January 20, 2006 Posted January 20, 2006 I don't know if this will help: [math]cot^{2}x = \frac{cos^{2}x}{sin^{2}x}[/math] or [math]\frac{csc^{2}x}{sec^{2}x}[/math] or [math]cot^{2}x = 1 + tan^{2}x[/math].
s pepperchin Posted February 16, 2006 Posted February 16, 2006 Are you saying that the field is in the X-Y direction and the pole sticks up in the Z direction with the angles being from the corners of the rectangle to the top of the pole?
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