[Tycho?] Posted January 20, 2006 Posted January 20, 2006 If t2 = 17.00 s for slinky (a), what is t1?'' That is all the information I have to complete this question, and I dont really know where to begin. t1 and t2 seem to be .16 of a full wavelenght apart, and the amplitude is given, but I can't seem to get any more useful information out of there. Or alternately, I dont know what to do with the information I do have. Any help on this would be appreciated. I doubt its actually very hard, but I really need some help on starting off.
timo Posted January 20, 2006 Posted January 20, 2006 I think you can assume constant velocity for the wave. Take a look at the points (0,0), (3,0) and (6,0).
timo Posted January 20, 2006 Posted January 20, 2006 I think you can assume constant velocity for the wave. Take a look at the points (0,0), (3,0) and (6,0). Oh, and btw: You were a bit hasty/confused with your assumptions, I think (or you´re simply a lazy writer): '] t1 and t2 seem to be .16 of a full wavelenght apart, [...'] Two times are 15 meters apart? ... and this reply was supposed to be an EDIT ...
[Tycho?] Posted January 20, 2006 Author Posted January 20, 2006 I think you can assume constant velocity for the wave. Take a look at the points (0' date='0), (3,0) and (6,0). Oh, and btw: You were a bit hasty/confused with your assumptions, I think (or you´re simply a lazy writer): Two times are 15 meters apart? ... and this reply was supposed to be an EDIT ...[/quote'] Yeah so I got it, simply half the time t2 of course. How does my assumption make the two times 15 meters apart? I'm not defending my assumption here, I dont know much about this sort of thing. So where did you get this 15 meters from?
timo Posted January 20, 2006 Posted January 20, 2006 The point was that you said two times are a fraction of wavelength apart. But since time is measured in seconds and wavelength has the unit meters this could have been a hint already that something is wrong or at least incomplete with the statement. The 15 meters where just an arbitrary choice for a distance. I simply stumbled over that statement because it made me think you have plotted three different waves. EDIT: But on 2nd thought I think I know what you meant: Between t1 and t2 the wave has travelled that distance - I simply didn´t understand it initially.
[Tycho?] Posted January 21, 2006 Author Posted January 21, 2006 The point was that you said two times are a fraction of wavelength apart. But since time is measured in seconds and wavelength has the unit meters this could have been a hint already that something is wrong or at least incomplete with the statement. The 15 meters where just an arbitrary choice for a distance. I simply stumbled over that statement because it made me think you have plotted three different waves. I meant that in that time the wave travelled a distance equal to that fraction of a wavelength. I still dont see what wrong with my assumption. Boy, this homework is making me feel as dumb as a brick, even basic problem solving stuff I'm having trouble with. Maybe I'm tired or something.
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now