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Cosmic Microwave Background Radiation


Mike T

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CAUSE OF CMBR

 

The Cosmic Microwave Background Radiation is portrayed as the clincher evidence to prove the credibility of the Big Bang Universe. The CMBR is portrayed as a perfect black body radiation curve.

 

However, here I will provide a hypothesis that refutes the link between the CMBR and the BB.

 

On page 266 of the Michael Zeilik book entitled ASTRONOMY, The Evolving Universe, sixth edition, is an illustration (figure 13.6) of the solar radiation curve as viewed outside our atmosphere in comparison to a black body radiation curve. I tried to locate a website with this illustration but cannot find one. Some others may have more luck.

Notice that at the peak temperature of the Sun’s curve, it extends above the BBRC by a certain amount and has a steeper incline on the high temperature side. I believe this enhancement is the result of ‘plasma radiation’ in addition to the atomic hydrogen radiation which conforms to the BBRC.

 

The Bohr atomic explanation of the hydrogen spectrum tells us how the photon pulses are generated and radiated. The transition of the electron from an outside orbit to an inner orbit is shown as the cause of the photon radiation emission.

I believe these electron transitions trace out a black body photon pulse in all the various electron transitions. The addition of all these pulse energies then trace out the BBRC.

Only electron transitions in closed orbits radiate the BBRC. The reason for this is that the electron velocity increases as it moves from the outer orbit to the inner orbit. At the same time, its orbital trajectory is being reduced from the larger outer orbit to the smaller inner orbit. The lead portion of these black body pulses is the lower energy portion of the pulse and then ends at the high energy portion of the pulse. This is just opposite to the way they are shown in the physics books.

 

Electron radiations in a plasma would radiate from a ‘hyperbolic orbital’ passage where the electron velocity is too high for capture into a closed orbit.

These photon pulses would trace out a ‘sign wave’ pulse rather than a BBRC pulse due to the variation of the electron’s velocity that does not come from a closed transitional orbit but just an open passage of the electron by the nucleus. .

 

These sign wave pulses then integrate at the high end of the BBRC to increase the BBRC’s peak to depart from the normal BBRC pulse as the illustration in the book shows.

 

Since the recombination period in the BB’s early history that also brought about the decoupling of the matter and energy, the supposed cause of the current CMBR, the transition from a plasma to matter would include a mix of some plasma radiation with the newly formed matter radiation.

Therefore, for the reasons given above, the current CMBR cannot be a remnant of the BB because it would not be a perfect BBRC as it is being attributed.

 

The current CMBR must then be the result of the particles in interstellar and intergalactic space that result from space dust and molecular particles where their radiations are the result of electron transitions within these particles. This would explain why the CMBR is a perfect BBRC.

 

Also, the predicted temperatures by Gamow et al (1948) of the CMBR of 5K and later revised to 10K were more inaccurate then McKellars (1941) interstellar observed radiation of 2.3K.

Considering that our interstellar space with this prediction is colder than the CMBR intergalactic space temperature of 2.73K, I would say this should be an example of colder radiations in space contributing to an average of 2.73K.

 

The Second Law of Thermodynamics says that heat will always flow from ‘hot to cold’ to equalize the temperature in a closed system. These space particles are then contributing to create an equalized temperature in space. This would be the CMBR.

 

History of the 2.7 K Temperature Prior to Penzias and Wilson,

 

http://www.dfi.uem.br/~macedane/history_of_2.7k.html

 

The only logical explanation for the CMBR is that it is a ‘Thermal Equalibrium’ temperature in a Steady State Universe.

 

Mike T

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The Bohr atomic explanation of the hydrogen spectrum tells us how the photon pulses are generated and radiated. The transition of the electron from an outside orbit to an inner orbit is shown as the cause of the photon radiation emission.

I believe these electron transitions trace out a black body photon pulse in all the various electron transitions. The addition of all these pulse energies then trace out the BBRC.

Only electron transitions in closed orbits radiate the BBRC. The reason for this is that the electron velocity increases as it moves from the outer orbit to the inner orbit. At the same time' date=' its orbital trajectory is being reduced from the larger outer orbit to the smaller inner orbit. The lead portion of these black body pulses is the lower energy portion of the pulse and then ends at the high energy portion of the pulse. This is just opposite to the way they are shown in the physics books.

[/quote']

 

No, atomic transitions do not give you a blackbody spectrum. If you contend otherwise, you have to provide experimental evidence that supports your new hypothesis.

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No, atomic transitions do not give you a blackbody spectrum. If you contend otherwise, you have to provide experimental evidence that supports your new hypothesis.

 

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If you refer to the 'energy levels' of the Bohr HA and deduce that these emissions are the result of electron transitions at the various energies, than you add them up to form a composite profile, it will result in a BBRC.

 

During these transitions, the electron moves with increasing velocities and reducing radiuses. These type of changes would create the energy lavels relative to the temperatures emitted which is what the BBRC implies.

 

You will notice that the stars do radiate curves that resemble the BBRC although they are not exact because of plasma radiation mixed in plus sunspots and solar eruptions that contribute to distortion.

 

Mike T

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