Democomputer Posted February 5, 2006 Posted February 5, 2006 Someone forwarded me a message with this website on it: http://www.mindreader.lx.ro There weren't a lot of people on the list, so I think that it may be pretty new. Anyway, it is a fake. How long will it take you to figure out how it works?
Connor Posted February 5, 2006 Posted February 5, 2006 it has to be a multiple of 9, all the multiples of 9 are the same symbol *yawn*
The Thing Posted February 6, 2006 Posted February 6, 2006 I'm predicting what it next shows in the crystal ball instead of it predicting what I'm thinking! T3h crystal ball hath been outwitted by t3h 1337 psych1c sk1llz0rz. No seriously, Connor's right. Multiples of 9. Mathematically, say you have a number 10x+y Add the digits: x+y Minus that from 10x+y, so 10x+y-x-y=9x. All multiples of 9, x depending on the tenth digit of your number. But that hardly matters when all of the multiples of 9 have the same symbol.
SilentQ Posted February 6, 2006 Posted February 6, 2006 May be generalised to base [math]k[/math] saying that a number is equal to [math]\sum_{i=0}^nk^ix_i[/math]. [math]\sum_{i=0}^nk^ix_i - \sum x = \sum_{i=0}^n(k^ix_i-x_i)[/math] [math]= \sum_{i=0}^n(k^i-1)x_i[/math] [math]= \sum_{i=0}^n(x_i\sum_{j=0}^{i-1}(k-1)k^j)[/math] We may bring the constant factor of [math]k-1[/math] out to the front of both sums, giving [math](k-1)\sum_{i=0}^n(x_i\sum_{j=0}^{i-1}k^j)[/math], which is obviously then a multiple of [math]k-1[/math].
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