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Posted

I'm predicting what it next shows in the crystal ball instead of it predicting what I'm thinking!

 

T3h crystal ball hath been outwitted by t3h 1337 psych1c sk1llz0rz.

 

No seriously, Connor's right. Multiples of 9. Mathematically, say you have a number 10x+y

 

Add the digits: x+y

 

Minus that from 10x+y, so 10x+y-x-y=9x.

 

All multiples of 9, x depending on the tenth digit of your number. But that hardly matters when all of the multiples of 9 have the same symbol.

Posted

May be generalised to base [math]k[/math] saying that a number is equal to [math]\sum_{i=0}^nk^ix_i[/math].

 

[math]\sum_{i=0}^nk^ix_i - \sum x = \sum_{i=0}^n(k^ix_i-x_i)[/math]

 

[math]= \sum_{i=0}^n(k^i-1)x_i[/math]

 

[math]= \sum_{i=0}^n(x_i\sum_{j=0}^{i-1}(k-1)k^j)[/math]

 

We may bring the constant factor of [math]k-1[/math] out to the front of both sums, giving [math](k-1)\sum_{i=0}^n(x_i\sum_{j=0}^{i-1}k^j)[/math], which is obviously then a multiple of [math]k-1[/math].

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