Guest Bob Posted October 1, 2003 Posted October 1, 2003 I'm not sure whether this is biology or chemistry so i place it in both forums. could somebody please help me answer this question about the Gibbs Donnan equilibrium. We start with 10 Na ions and 10 Cl ions in each of the plasma and interstitial fluid compartments. Into the plasma compartment we add 60 negatively charged protein molecules together with 60 Na ions to maintain electrical neutrality. According to the Gibbs- Donnan equilibrium what is the final distribution of ions?
Dudde Posted October 1, 2003 Posted October 1, 2003 please post your question once, and once only. If you're not sure where to put it, guess, or put it in the general science forum. it's been too long since I've done any of that kind of science, so I'll let someone smarter than I answer:D
wolfson Posted November 16, 2003 Posted November 16, 2003 Ok [na]in = [na]out [cl]in = 2 p out K= [cl]^2]r*p^2 So the arrangemnt of the ioistaion level would be using log, Kp(out)(in)*(nacl)ou in seem complicated i know but its not that bad..... so [na]in =[na]out Arrangagment = _incl.cations and anions): Inside = 18na+ 8cl- 10a- Outside = 12Na+ 12cl- i hope this helps remeber Kp = {in}o/{out}o = p^kv The answer is whats in and out its BIOLOGY by the way and also there is a net imbalance of cations (positive) and anions (negative) across the membrane, 18/12 and 8/12 respectively. This represents a potential difference across the membrane. But just show the in and out {k} opps i mean [k] i like them more lol
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