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It is soluble in a concentrated NaOH solution. This is due to formation of so-called plumbate (II) anions. Lead (II) is amphoteric. It can react as a base, but also as an acid. Many metal-ions are amphoteric (other examples are Al(3+), Cr(3+), Sb(3+), Be(2+), and even Cu(2+) to a little extent).

 

PbCl2 + 2OH(-) --> Pb(OH)2 + 2Cl(-)

 

Pb(OH)2 + 2OH(-) --> PbO2(2-) + 2H2O

 

The solution has to be fairly strongly alkaline before Pb(OH)2 dissolves. I do not know how much Pb(OH)2 dissolves, but I think a fairly large amount.

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