computerages Posted February 24, 2006 Share Posted February 24, 2006 hi every1~ I had the following question on one of my physics quiz, and I need some explanation on how'd you answer it. "A bat detects an object 6 seconds after it emits a high frequency sound of 50,000Hz into aid at STP. How far away is the object from the bat?" That's how I solved the problem: [math] d=t*v=6*331=1986m=d [/math] But my teacher said that I was supposed to use 3 sec. instead of 6. As far as I am concerned, it can be because of taking three sec. to go forward, and the other three to move back. I am not sure what it really means, but just a thought. Link to comment Share on other sites More sharing options...
swansont Posted February 24, 2006 Share Posted February 24, 2006 What you solved for was how far the signal traveled, which is the round-trip distance. Link to comment Share on other sites More sharing options...
5614 Posted February 24, 2006 Share Posted February 24, 2006 As in it took 6 seconds for the signal to go to the object AND back to the bat. So it took 3 seconds to reach the object, and then another 3 for the signal to come back to the bat. Link to comment Share on other sites More sharing options...
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