computerages Posted February 24, 2006 Posted February 24, 2006 hi every1~ I had the following question on one of my physics quiz, and I need some explanation on how'd you answer it. "A bat detects an object 6 seconds after it emits a high frequency sound of 50,000Hz into aid at STP. How far away is the object from the bat?" That's how I solved the problem: [math] d=t*v=6*331=1986m=d [/math] But my teacher said that I was supposed to use 3 sec. instead of 6. As far as I am concerned, it can be because of taking three sec. to go forward, and the other three to move back. I am not sure what it really means, but just a thought.
swansont Posted February 24, 2006 Posted February 24, 2006 What you solved for was how far the signal traveled, which is the round-trip distance.
5614 Posted February 24, 2006 Posted February 24, 2006 As in it took 6 seconds for the signal to go to the object AND back to the bat. So it took 3 seconds to reach the object, and then another 3 for the signal to come back to the bat.
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now