david.017 Posted March 7, 2006 Posted March 7, 2006 Hey, I'm currently struggle with these two proofs, if anyone can help me I would be very thankful. 1. prove that one of the roots of x^3+ax^3 +bx + c = 0 is the negative of another if and only if c=ab. 2. Prove that if the diagonals of a quadrilateral divide it into four triangles of equal area, then the quadrilateral is a parallelogram.
matt grime Posted March 9, 2006 Posted March 9, 2006 What have you done for one? how have you tried to use the hypothesis?
grayfalcon89 Posted March 13, 2006 Posted March 13, 2006 For #2: WLOG, let ABCD be a quadrilateral. Let AC and BD intersect at E. By the problem, we know that [AEB] = [bEC] = [AED] = [DEC]. Since <AEB = <DEC, we know that AE*BE = CE*ED. Similar argument gives AE*DE = CE*BE. Solving for AE in both sides, we get AE = (CE*ED)/BE and AE = (CE*BE)/ED. They're equal so: (CE*ED)/BE = (CE*BE)/ED --> CE*ED*ED = BE*CE*BE. Simplifying, ED^2 = BE^2 and since this is the side of the figure, we know that it has to be positive and can take square root so ED = BE. Solving for other variable will also give AE = CE. Since the diagonals bisect each other, ABCD has to be parallelogram. The area ratio came from the vertical angles and the formula a*b*sinC*1/2.
Leison Posted March 13, 2006 Posted March 13, 2006 for #2, i think quadrilateral will be a square or rhombus, not a general paralellogram
the tree Posted March 13, 2006 Posted March 13, 2006 for #2' date=' i think quadrilateral will be a square or rhombus, not a general paralellogram[/quote']Being a square or rhombus, makes something a paralellogram.
Dave Posted March 14, 2006 Posted March 14, 2006 For number one, if the cubic has two roots a and -a, then it must have a factor of (x-a)(x+a). You should be able to use this to prove one direction. For the other direction; just make the obvious first step
Leison Posted March 14, 2006 Posted March 14, 2006 Being a square or rhombus, makes something a paralellogram. u can't have 4 triangles of equal areas in a general parallelogram but the question is asking to prove for general parallelogram. the question should be modified.
s pepperchin Posted March 14, 2006 Posted March 14, 2006 Hey' date=' I'm currently struggle with these two proofs, if anyone can help me I would be very thankful. 1. prove that one of the roots of x^3+ax^3 +bx + c = 0 is the negative of another if and only if c=ab. 2. Prove that if the diagonals of a quadrilateral divide it into four triangles of equal area, then the quadrilateral is a parallelogram.[/quote'] I just want to confirm that the exponent in the second term is a 3 just like the first term.
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