labview1958 Posted March 20, 2006 Share Posted March 20, 2006 Let's say I have two pairs of identical magnets. The first pair is 1 Tesla. The second pair is 2 Tesla. If I have unlike poles facing each other as below, would the total force on the balance be the same? 1T2T 1T2T Balance 0r 1T2T 2T1T Balance Link to comment Share on other sites More sharing options...
[Tycho?] Posted March 20, 2006 Share Posted March 20, 2006 I'm not sure what you are asking here. I can't visualize your problem, could you try to rephrase it? Link to comment Share on other sites More sharing options...
labview1958 Posted March 20, 2006 Author Share Posted March 20, 2006 Sorry. It's like poles facing each other. The bottom pair is placed on a weighing machine. The upper pair is held up by a retort stand etc. Let's all have north poles face each other. First Kes. 1 Tesla faces 1 Tesla 2 Tesla faces 2 Tesla. Second kes. 1 Tesla faces 2 Tesla 2 Tesla faces 1 Tesla. Would the weighing machine register the same force? Link to comment Share on other sites More sharing options...
Meir Achuz Posted March 20, 2006 Share Posted March 20, 2006 No. The force would be greater in the first case. When a strong magnet faces a weaker magnet, N to N, the stronger magnet tends to demagnetize the weaker magnet. A strong N opposite a weak enough N can even attract. Link to comment Share on other sites More sharing options...
Meir Achuz Posted March 20, 2006 Share Posted March 20, 2006 Even if there were no demagnetization of the weaker magnet, the ratio of forces would be 5/4. Link to comment Share on other sites More sharing options...
LazerFazer Posted March 20, 2006 Share Posted March 20, 2006 How would you calculate the force of repulsion between the two magnets? LF Link to comment Share on other sites More sharing options...
labview1958 Posted March 20, 2006 Author Share Posted March 20, 2006 What about the diagonal repulsion. Is that taken into account? What if I rotate a smaller like pole over a much larger like pole. Would the weighing machine register a constant or a variable force, assuming the weighing machine is accurate to 0.0001g? Link to comment Share on other sites More sharing options...
Meir Achuz Posted March 21, 2006 Share Posted March 21, 2006 How would you calculate the force of repulsion between the two magnets? LF Most texts don't do this. In order to push two bar magnets together would take a force F=2\pi MM'A, where M and M' are the magnet strengths in gauss, A the area in cm^2, and F is in dynes. Actually, the force would be somewhat less than this due to the demagnetization, which depends on the actual material of the magnets. Link to comment Share on other sites More sharing options...
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