kidia Posted March 21, 2006 Posted March 21, 2006 How can I Compare the magnitudes near the earth’s surface of the weight of an electron and a typical magnetic force exerted by the earth’s magnetic field (B = 10-5T) on an electron with speed 10 m/s. As I understood Weight of electron = mg Magnetic force=qBv am I right?
timo Posted March 21, 2006 Posted March 21, 2006 Mostly. Strictly speaking the magnitude of the magnetic force is qBv*|sin(a)| where a is the angle between the direction of the magnetic field lines and the movement direction of the electron. But if you´re only interested in the case where the electron moves perpendicular to the field, then your equations are ok.
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