kidia Posted March 25, 2006 Posted March 25, 2006 I have one question here,I fail to understood what is Q of the system,is anybody has an ideal on this? An object of mass 2 kg hangs from spring of negligible mass. The spring is extended by 2.5 cm when the object is attached. The top end of the spring is oscillated up and down in SHM with amplitude of 1 mm. The Q of the system is 15. What is angular frequency for this system?
swansont Posted March 25, 2006 Posted March 25, 2006 IIRC, Q basically tells you how effficiently you transfer the energy. High Q means small losses and large amplitudes when you are near resonance, i.e. the added energy goes into the oscillation, not lost to damping. How far the spring extends with the mass on it should give you k, the resonance frequency is given by k and m, and the Q factor should give you the damping coefficient. Do you have an equation that lets you solve for oscillation frequency in terms of these factors?
Templar Posted March 27, 2006 Posted March 27, 2006 I have one question here' date='I fail to understood what is Q of the system,is anybody has an ideal on this? An object of mass 2 kg hangs from spring of negligible mass. The spring is extended by 2.5 cm when the object is attached. The top end of the spring is oscillated up and down in SHM with amplitude of 1 mm. The Q of the system is 15. What is angular frequency for this system?[/quote'] For equation [math]m\frac{d^2 x}{dt^2} = -kx -b\frac{dx}{dt}[/math] they're defined as [math]\omega_0 = \sqrt{\frac{k}{m}}[/math] [math]Q = \frac{\omega_0 m}{b}[/math] I assume you know how to solve this equation.
swansont Posted March 27, 2006 Posted March 27, 2006 [math]Q = \frac{\omega_0 m}{b}[/math] I thought Q was dimensionless [math]Q = \frac{\omega_0}{b}[/math]
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