Norman Albers Posted April 5, 2006 Posted April 5, 2006 If two bodies of roughly equal mass coalesce into a condensed form (neutron star or black hole) would we experience dipole waves? If the masses are different are there then quadrupole components?
RyanJ Posted April 5, 2006 Posted April 5, 2006 If two bodies of roughly equal mass coalesce into a condensed form (neutron star or black hole) would we experience dipole waves? If the masses are different are there then quadrupole components? I believe this has the answers your looking for A new client for me to install, Einstein@Home, sounds like its for a useful cause Cheers, Ryan jones
5614 Posted April 5, 2006 Posted April 5, 2006 Einstein@Home thread: http://www.scienceforums.net/forums/showthread.php?t=7536 (first link in first post no longer works, but the 2nd one still does)
Norman Albers Posted April 5, 2006 Author Posted April 5, 2006 Thanks, sorry I didn't realize it was often so easy to Wiki answers to well-placed questions. I read that first list and am enlightened to read that radiation happens predominantly with a changing quadrupole moment. It also said that dipole mode is possible but gave no detail. Anyway I started off bass ackwards since a symmetric dumbell is only quadrupole, yah? Then too, is an unbalanced pair simply similar about its center of mass? . . . . . . . . . . The implication seems to be that we will observe frequency sweep upward. If you hear my message end in such a chirp, assume I have imploded.. . . . . . . . . A FEW HOURS LATER: I see it says that a 'dumbell' of changing length radiates; also does a rotating dumbell of stable orbit. That sort of signal does not chirp. Is this a fair summary?
Norman Albers Posted April 6, 2006 Author Posted April 6, 2006 If there was a nearly head-on collision, one of low angular momentum, what would be the nature of the signal? I will hazard a guess that there is none, because a changing quad. moment is not the same as an oscillating one. In electromagnetics, dipole time derivative matters; here it might be the second-order derivative.
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