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Calculate the pH of the solution which results from the mixing of 100.0 mL of

0.050 NaOH solution with an equal volume of 0.10 M HCl solution.

 

Seems straight forward to me. Strong acid and a strong base, so they'll react completely. You end up with .05M HCl, which is the molarity of H+, so you can just use -log(.05) to get the pH. I get 1.3.

 

But this is apparently incorrect, the answer given is 1.6. Can someone tell me where I went wrong?

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