[Tycho?] Posted April 16, 2006 Posted April 16, 2006 Calculate the pH of the solution which results from the mixing of 100.0 mL of 0.050 NaOH solution with an equal volume of 0.10 M HCl solution. Seems straight forward to me. Strong acid and a strong base, so they'll react completely. You end up with .05M HCl, which is the molarity of H+, so you can just use -log(.05) to get the pH. I get 1.3. But this is apparently incorrect, the answer given is 1.6. Can someone tell me where I went wrong?
insane_alien Posted April 16, 2006 Posted April 16, 2006 the volume doubles. so you have to half the concentration .
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