[Tycho?] Posted April 16, 2006 Share Posted April 16, 2006 Calculate the pH of the solution which results from the mixing of 100.0 mL of 0.050 NaOH solution with an equal volume of 0.10 M HCl solution. Seems straight forward to me. Strong acid and a strong base, so they'll react completely. You end up with .05M HCl, which is the molarity of H+, so you can just use -log(.05) to get the pH. I get 1.3. But this is apparently incorrect, the answer given is 1.6. Can someone tell me where I went wrong? Link to comment Share on other sites More sharing options...
insane_alien Posted April 16, 2006 Share Posted April 16, 2006 see your other thread on the same Link to comment Share on other sites More sharing options...
AL Posted April 16, 2006 Share Posted April 16, 2006 Did you take into account dilution? If you add an equal volume of HCl, you now have 200.0 mL of solution. Link to comment Share on other sites More sharing options...
insane_alien Posted April 16, 2006 Share Posted April 16, 2006 yeah i said that in his other thread. seen that one before this. he didn't take into account the dilution. Link to comment Share on other sites More sharing options...
[Tycho?] Posted April 16, 2006 Author Share Posted April 16, 2006 Ohhhhh right. That crazy dilution. Thanks guys, I knew it was something stupid like that. Link to comment Share on other sites More sharing options...
Borek Posted April 16, 2006 Share Posted April 16, 2006 Well, you were already told that the problem is in dilution, but here is almost identical pH calculation question with explanation. Best, Borek -- Chemical calculators at www.chembuddy.com www.pH-meter.info Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now